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116y^2-104y-149=0
a = 116; b = -104; c = -149;
Δ = b2-4ac
Δ = -1042-4·116·(-149)
Δ = 79952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{79952}=\sqrt{16*4997}=\sqrt{16}*\sqrt{4997}=4\sqrt{4997}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{4997}}{2*116}=\frac{104-4\sqrt{4997}}{232} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{4997}}{2*116}=\frac{104+4\sqrt{4997}}{232} $
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